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Add some ASCII art explaining mux decomposition
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@ -214,6 +214,27 @@ module \$__XILINX_SHIFTX (A, B, Y);
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assign Ax = {A[1], A};
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\$__XILINX_MUXF78 fpga_hard_mux (.I0(Ax[0]), .I1(Ax[2]), .I2(Ax[1]), .I3(Ax[3]), .S0(B[1]), .S1(B[0]), .O(Y));
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end
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// Note that the following decompositions are 'backwards' in that
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// the LSBs are placed on the hard resources, and the soft resources
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// are used for MSBs.
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// This has the effect of more effectively utilising the hard mux;
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// take for example a 5:1 multiplexer, currently this would map as:
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//
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// A[0] \___ __ A[0] \__ __
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// A[4] / \| \ whereas the more A[1] / \| \
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// A[1] _____| | obvious mapping A[2] \___| |
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// A[2] _____| |-- of MSBs to hard A[3] / | |__
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// A[3]______| | resources would A[4] ____| |
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// |__/ lead to: 1'bx ____| |
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// || |__/
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// || ||
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// B[1:0] B[1:2]
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//
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// Expectation would be that the 'forward' mapping (right) is more
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// area efficient (consider a 9:1 multiplexer using 2x4:1 multiplexers
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// on its I0 and I1 inputs, and A[8] and 1'bx on its I2 and I3 inputs)
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// but that the 'backwards' mapping (left) is more delay efficient
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// since smaller LUTs are faster than wider ones.
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else if (A_WIDTH <= 8) begin
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wire [8-1:0] Ax = {{{8-A_WIDTH}{1'bx}}, A};
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wire T0 = B[2] ? Ax[4] : Ax[0];
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