check xml domain name vs xml filename

Signed-off-by: Jeff Carr <jcarr@wit.com>

xml.go

@@ -6,7 +6,9 @@ import (
 	"encoding/xml"
 	"fmt"
 	"os"
+	"path/filepath"
 	"reflect"
+	"strings"
 
 	"go.wit.com/log"
 	"libvirt.org/go/libvirtxml"
@@ -76,6 +78,9 @@ func addDefaults(d *libvirtxml.Domain, filename string) {
 func readXml(filename string) (*libvirtxml.Domain, error) {
 	log.Verbose("parse xml file:", filename)
 
+	hostname := filepath.Base(filename)
+	hostname = strings.TrimSuffix(hostname, ".xml")
+
 	pfile, err := os.ReadFile(filename)
 	if err != nil {
 		log.Println("ERROR:", err)
@@ -89,6 +94,13 @@ func readXml(filename string) (*libvirtxml.Domain, error) {
 		log.Info("Marshal failed on file", filename, err)
 		return nil, ErrorParseXML
 	}
+
+	if domcfg.Name != hostname {
+		log.Info("ERROR: domcfg.Name != name", domcfg.Name, hostname)
+		log.Info("ERROR: xml filenames must match the xml name")
+		os.Exit(-1)
+	}
+
 	return domcfg, nil
 }