target: Correct profiling calculation
1. high_pc should be (maximum sample + 1) (Refer to gprof source code) 2. bucket index should be sample offset --------------- x (number of bucket) sample range For example, if minimum sample is 0 and maximum sample is 5 and the number of bucket is 3. a = sampled_address - 0 b = 3 c = 6 (a, b, c refer to source code variables) sampled_address = 0, => a = 0, => bucket_index = 0 sampled_address = 1, => a = 1, => bucket_index = 0 sampled_address = 2, => a = 2, => bucket_index = 1 sampled_address = 3, => a = 3, => bucket_index = 1 sampled_address = 4, => a = 4, => bucket_index = 2 sampled_address = 5, => a = 5, => bucket_index = 2 Change-Id: Ia9fa0e4d9c7183e3e9d7ceaf73e63729f07aa2ce Signed-off-by: Hsiangkai Wang <hsiangkai@gmail.com> Reviewed-on: http://openocd.zylin.com/1607 Tested-by: jenkins Reviewed-by: Spencer Oliver <spen@spen-soft.co.uk>
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@ -3387,7 +3387,11 @@ static void writeGmon(uint32_t *samples, uint32_t sampleNum, const char *filenam
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max = samples[i];
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}
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int addressSpace = (max - min + 1);
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/* max should be (largest sample + 1)
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* Refer to binutils/gprof/hist.c (find_histogram_for_pc) */
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max++;
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int addressSpace = max - min;
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assert(addressSpace >= 2);
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static const uint32_t maxBuckets = 16 * 1024; /* maximum buckets. */
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@ -3403,8 +3407,8 @@ static void writeGmon(uint32_t *samples, uint32_t sampleNum, const char *filenam
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for (i = 0; i < sampleNum; i++) {
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uint32_t address = samples[i];
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long long a = address - min;
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long long b = numBuckets - 1;
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long long c = addressSpace - 1;
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long long b = numBuckets;
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long long c = addressSpace;
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int index_t = (a * b) / c; /* danger!!!! int32 overflows */
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buckets[index_t]++;
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}
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